Mathematics
WAEC 2005
Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the value of k
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A.
-4
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B.
-2
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C.
-1
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D.
\(-\frac{1}{4}\)
Correct Answer: Option A
Explanation
Substituting for x in the equation
\(2(2)^2 + (k+2)2+k = 0 \Rightarrow 8 +2k + 4 + k =0 \Rightarrow 3k =-12; k=-4\)
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