In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s...

Mathematics

WAEC 2005

In the diagram, PR is a diameter, ∠PRQ = (3x-8)^o and ∠RPQ = (2y-7)^o. s x in terms of y

A. \(x=\frac{75-2y}{3}\)
B. \(x=\frac{105-3y}{2}\)
C. \(x=\frac{105-2y}{3}\)
D. \(x=\frac{75-3y}{2}\)

WAEC and NECO CBT Software for Computers and Laptops - Candidates, Schools, Centres, Resellers - 100% Offline -Download Now

Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts

Your School's Whatsapp Group - Join Us now

Correct Answer: Option C

Explanation

180 = ∠RPQ + ∠PRQ + ∠PQR Since PQR = 90 (theorem: angle in a semi circle)
180 = ∠RPQ + ∠PRQ + 90 => 180^o = (3x-8)^o+(2y-7)^o+90^o; 90+8+7 = 3x+2y =>\(\frac{105-2y}{3}=x\)

Previous Next

Go back to Maths classroom

Report an Error Ask A Question Download App

Contributions ({{ comment_count }})

Please wait...

{{ settings.no_comment_msg ? settings.no_comment_msg : 'There are no comments' }}

Quick Questions

when is mop up exam starting? Answer this

2 Answers · 4 days ago
if my aggregate is 65 percent can I study economic in lasu? Answer this

1 Answers · 1 day ago
pls Can I get to see one of u guys slip which was given to after ur registration for jamb? Answer this

1 Answers · 4 hours ago

WAEC and NECO CBT App for Mobile Devices - Candidates, Schools, Centres, Resellers - 100% Offline -Download Now

In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s...

Correct Answer: Option C

Explanation

Contributions ({{ comment_count }})

Please wait...

Modal title

Report

Block User

{{ feedback_modal_data.title }}

Quick Questions

Post your Contribution

Sign In