Correct Answer: Option D

Explanation

x2 (sum of roots)x + (product of roots) = 0
Sum of roots \(2+-3\frac{1}{2} = -1\frac{1}{2} = -\frac{1}{2}\)
Product of roots \(= 2 \times - 3\frac{1}{2}\) = -7
x\(^2\) - \(\frac{-3}{2}\)x + (-7) = 0 ⇒ 2x\(^2\) + 3x - 14 = 0

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