Find the range of values of x for which\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\)
\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\) \(\frac{3(x+2)-4(x+1)>6}{12}\); 3x + 6 – 4x – 4 > 6 - x + 2 > 6; - x > 4; x < -4
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