Given that sin (5x - 28)^o = cos (3x - 50)^o,0 < x < 90^o, find the value of x

Silentgeez

1 year ago

Given that sin (5x - 28)o = cos (3x - 50)o,0 < x < 90o, find the value of x

To find the value of x, we can use the trigonometric identities sin(90°-θ) = cos(θ) and cos(90°-θ) = sin(θ).

Given sin(5x-28)° = cos(3x-50)°, we can rewrite this as sin(90° - (5x-28)) = sin(3x-50)°.

This simplifies to sin(90° - 5x + 28) = sin(3x-50)°.

Since both angles have the same sine value, the angles must be equal:

90° - 5x + 28 = 3x - 50.

Solving for x gives:

90° + 28 + 50 = 3x + 5x,

168 = 8x,

x = 21.

Therefore, the value of x is 21°.Why birds are