Correct Answer: Option B

Explanation

\(23_{five} = X_{ten}; X_{ten}\) = 2\(\times 5^1 + 3\times 5^0 = 10 + 3 = 13\)
101\(_{three}\) = P\(_{ten}\); P\(_{ten}\) = 1\(\times 3^2 + 0\times 3^1 + 1\times 3^0 = 9 + 0 + 1 = 10_{ten}\)
Y = 13+10=23\(_{ten}\);
Converting to base two
\(\begin{matrix}
2 & 23\\
2 & 11 &R1\\
2 & 5 & R1\\
2 & 2 & R1\\
2 & 1 & R0\\
& 0& R1 \uparrow\\
\end{matrix}\)
= y = 10111\(_2\)

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