Correct Answer: Option D

Explanation

\(\frac{4}{a-3}-\frac{1}{a+3}\)

= \(\frac{4(a+2)-1(a-3)}{(a-3)(a+2)}\)

\(\frac{4a+8 -a +3}{(a-3)(a+2)}\)

= \(\frac{3a+11}{(a-3)(a+2)}\)

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