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A.
\(\frac{x+3}{1-x^2}\)
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B.
\(\frac{x-3}{1+x^2}\)
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C.
\(\frac{3-x}{1-x^2}\)
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D.
\(\frac{3-x}{1+x^2}\)
Correct Answer: Option C
Explanation
\(\frac{1}{1-x} + \frac{2}{1+x}\\
\frac{1+x+2-2x}{(1-x)(1+x)} = \(\frac{3-x}{1-x^2}\)\)
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