A box contains 5 red, 3 green and 4 blue balls. A boy is allowed to take away two balls from the box. What is the probability that the two balls are red?
Total number of balls = 5 + 3 + 4
= 12 balls
P(first ball is red) = \(\frac{5}{12}\)
P(second ball is red) = \(\frac{4}{11}\)
\(\therefore\) P(both balls are red) = \(\frac{5}{12} \times \frac{4}{11}\)
= \(\frac{5}{33}\)
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