A box contains 5 red, 3 green and 4 blue balls. A boy is allowed to take away two balls from the box. What is the probability that the two balls are red?

a

\(\frac{5}{33}\)

b

\(\frac{5}{36}\)

c

\(\frac{103}{132}\)

d

\(\frac{31}{36}\)

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Correct Option
a

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the answer is 5/32

Gidex200
4 months ago

I don't understand very well

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