If \(y \propto \frac{1}{\sqrt{x}}\) and x = 16 when y = 2, find x when y = 24
\(\frac{1}{9}\)
\(\frac{1}{6}\)
\(\frac{1}{3}\)
\(\frac{2}{3}\)
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Wrong. The answer is 1/9.
An explanation.
Here goes...
Y=1/√x is the equation given and in the 1st sentence, y=2 and x=16. Fixing em to the equation, you'll get... 2=k/√16(where k Is ya constant)
2=k/4(cross multiply)
K=8. Cuz we have gotten our value for y we'll have to fix it to the equation(y=k/√x)
In the 2nd sentence y=24 and we are told to find x.
Then we say... 24=8/√x by cross multiplying, we'll get
24√x=8
(24√x)²=8²(to remove the root sign we have to square boths sides)
576 x X =64
576x=64
X=64/576
X=1/3.
Please submit your answers with a detailed explanation. Thanks for your contributions.
I tink the question is d problem dere
Cos the square root is 1/3 is part of the options dere
