Find the value of x such that the expression \(\frac{1}{x}+\frac{4}{3x}-\frac{5}{6x}+1\) equals zero
a
\(\frac{1}{6}\)
b
\(\frac{1}{4}\)
c
\(\frac{-3}{2}\)
d
\(\frac{-7}{6}\)
Explanation
Correct Option
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Sojoel
11 years ago
1/x+4/3x-4/6x+1=0
L.C.M=6x
6+8-5+6x/6x=0
9+6x=0*6x
9+6x=0
collect like terms
6x=-9
x=-3/2.
