In the diagram, AB is a vertical pole and BC is horizontal. If |AC| = 10m and |BC| = 5m, calculate the angle of depression of C from A
In triangle ABC, \(\frac{BC}{AC} = \cos \theta\)
\(\implies \cos \theta = \frac{5}{10} = 0.5\)
\(\theta = \cos^{-1} (0.5) = 60°\)
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