The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men
a
45 years
b
72 years
c
108 years
d
216 years
Explanation
Correct Option
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philipson Andrew
10 years ago
explanation...let their ages=X...3+4+5=
now....difference BTW highest and lowest=18
then.....5x/12-3x/12=18
...........2x/12=18
.........cross multiply...2x=216
divide both sides by 2....x=108
now...substitute value of x into their ages
...........5(108)/12=45
............4(108)/12=36
...........3(108)/12=27
.....now....45+36+27=108
