In the diagram, CDE is a triangle, ABEF is cyclic quadrilateral, AB||CD, ∠BAF = 65^o and ∠AFE = 85^o calculate ∠CDE

20^o

30^o

50^o

65^o

Download Offline App Ask a Question

Explanation

Correct Option

No explanation available

Video Explanation

No video available

Post your Contribution

ExcellentDieu

3 years ago

fab=beg (opposite angles in a cylic quadrilateral)
afe=ebg (opposite angles in a cylic quadrilateral)
bcd=ebg(F-angles)
∆CDE
180-(ecd+ced)
180-(85+65)=30°
cde 30°

Ola1234567890000

1 year ago

The diagram is not shown so I could not answer the question.

Quick Questions

Ask a Question

ceoofwahala

20th June, 2026

Chemistry

2 comments

ASSAAS

20th June, 2026

English Language

5 comments

infinitehoaxx

21st May, 2026

Computer

4 comments

In the diagram, CDE is a triangle, ABEF is cyclic quadrilateral, AB||CD, ∠BAF = 65o and ∠AFE = 85o calculate ∠CDE

Explanation

Video Explanation

Discussions (2)

In the diagram, CDE is a triangle, ABEF is cyclic quadrilateral, AB||CD, ∠BAF = 65^o and ∠AFE = 85^o calculate ∠CDE