Mathematics
WAEC 1999
In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
-
A.
x
-
B.
\(\frac{x^2}{y}\)
-
C.
\(\frac{y}{x^2}\)
-
D.
\(\frac{y^2}{x}\)
Correct Answer: Option D
Explanation
\(\frac{x}{x+y}=\frac{y}{x+CE}\\
xy + xCE = xy + y^2\\
∴xCE = y^2\\
CE=\frac{y^2}{x}\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}