Given that m = -3 and n = 2 find the value of \(\frac{3n^2 - 2m^3}{m}\)
Given that m = -3, n = 2, the value of \(\frac{3n^2 - 2m^3}{m}\) \(\frac{3(2)^2 -2(-3)^3}{-3} = \frac{12+54}{-3}\) = -22
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