It is observed that \(1 + 3 = 2^2, 1 + 3 + 5 = 3^2, 1 + 3 + 5 + 7 = 4^2\).
If 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 = P\(^2\) find P
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 = 64
where 64 = 8\(^2\)
That is, P is 8
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