In ∆PQR. ∠PQR is a right angle. |QR| = 2cm and ∠PRQ = 60o. Find |PR|
cos60 = \(\frac{adj}{hyp}\)
cos60 = \(\frac{2}{x}\)
x = \(\frac{2}{cs60}\) = 2 x \(\frac{2}{1}\) = 4cm
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