Correct Answer: Option D

Explanation

\(\frac{x}{x-2}-\frac{x+2}{x+3}\)

\(\frac{[x][x+3] - ([x+2][x-2])}{[x-2][x+3]}\)

= \(\frac{x^2 + 3x - (x^2 - 4)}{[x-2][x+3]}\)

=  \(\frac{3x + 4}{[x-2][x+3]}\)

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