Express as a single fraction: \(\frac{x}{x-2}-\frac{x+2}{x+3}\)
a
\(\frac{2x^2 - 3x - 4}{(x-2)(x+3)}\)
b
\(\frac{2x^2 + 3x - 4}{(x-2)(x+3)}\)
c
\(\frac{2}{(x-2)(x+3)}\)
d
\(\frac{ 3x + 4}{(x-2)(x+3)}\)
e
\(\frac{3x - 4}{(x-2)(x+3)}\)
Explanation
Correct Option
dVideo Explanation
No video available
Post your Contribution
Share:
Discussions (9)
SweetIvy
5 months ago
The answer is D. Make sure you put all the values you got from x+2 in a bracket, then you multiply all of them with the minus that is infront of the bracket.
