Given that \(\frac{6x-y}{x+2y}=2\), find the value of \(\frac{x}{y}\)
a
\(\frac{3}{8}\)
b
\(\frac{5}{8}\)
c
\(\frac{4}{5}\)
d
\(\frac{5}{4}\)
e
\(\frac{8}{5}\)
Explanation
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Discussions (8)
Igber
6 years ago
6x - y / x + 2y = 2 -------(1)
=> 6x - y = 2x + 4y + y
=> 6x - 2x = 4y + y
=> 4x = 5y (making x subject) we have,
x =5y/4 ------(2)
substituting the value of x in eqn. 1, we get
6 (5y/4) -y / 5y/4 + 2y = 2
=>30y/4 -y /5y/4 + 2y = 2
=> 30y-4y/4 ÷5y+8y/4 = 2
=> 26y/4÷13y/4 = 2
=26y/4 * 4/13y =2
=> 2y = 2
=>y = 1
=>x =5 (1)/4= 5/4
Therefore, X/Y => 5/4÷1 =5/4 .
Alicia24434
1 year ago
After The Explanations And Solutions The Selected Answer Is x\y =5\4 instead Of x\y=4\5
