Given that \(\frac{1}{2} \log_{10} P = 1\), find the value of P.
\(\frac{1}{2} \log_{10} P = 1\)
\(\log_{10} P^{\frac{1}{2}} = 1\)
\(P^{\frac{1}{2}} = 10^{1}\)
\(\implies P = 10^{2}\)
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}