Make q the subject of the relation t = √(pq/r - r\(^2\)q)
a
q = \(\frac{rt^2}{(p - r^3)}\)
b
q = \(\frac{t^2}{(p - r^2)}\)
c
q = \(\frac{rt}{(p - r^3)}\)
d
q = \(\frac{(p - r^3)}{rt^2}\)
e
q = rt\(^2\)(p - r\(^3\))
Explanation
Correct Option
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Discussions (8)
waliheart
11 years ago
SO SAD...u ar beta start again from nursery 1
ur answer is wrong my dear.
answer is q= (rt^2 - r63)/p
