A bag contains 3 red, 4 black and 5 green identical balls. Two balls are picked at random, one after the other without replacement. Find the probability that one is red and the other is green
Total balls = 12
RG or GR
\(\frac{3}{12}\) x \(\frac{5}{11}\) + \(\frac{5}{12}\) x \(\frac{3}{11}\)
= \(\frac{5}{44}\) + \(\frac{5}{44}\)
=\(\frac{10}{44}\)
=\(\frac{5}{22}\)
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