A bag contains 3 red, 4 black and 5 green identical balls. Two balls are picked at random, one after the other without replacement. Find the probability that one is red and the other is green
a
\(\frac{2}{3}\)
b
\(\frac{5}{11}\)
c
\(\frac{5}{22}\)
d
\(\frac{5}{24}\)
e
\(\frac{5}{48}\)
Explanation
Correct Option
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