Make p the subject if formula y = \(\frac{a + p}{a - p}\)
a
\(p = \frac{a(y - 1)}{y + 1}\)
b
\(p = \frac{2a - y}{a + y}\)
c
\(p = \frac{ay}{y + 1}\)
d
\(p = \frac{2y - 1}{y - 1}\)
Explanation
Correct Option
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Overwatch886
2 years ago
I do not think this answer is correct. We should have
y = (a^2 + p - ap)/a
then ay = a^2 + p - ap
Then ay - a^2 = p(1 - a)
Then P = (a(y - a))/(1 - a)
