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In the diagram above, PQ is parallel to TU, ∠PQR = 50°, ∠QRS = 86° and ∠STU...

Mathematics
WAEC 1995

In the diagram above, PQ is parallel to TU, ∠PQR = 50°, ∠QRS = 86° and ∠STU = 64°. Calculate the value of x.

  • A. 136o
  • B. 120o
  • C. 108o
  • D. 100o
  • E. 96o
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Correct Answer: Option D
Explanation

y = 86° - 50° [Alternate ∠s are equal]

y = 86° - 50° = 36°

a = y = 36° [Alternate ∠s]; b = 64° [Alternate ∠s;]

x = a + b = (36° + 64°)

=100°


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