In the diagram, |PS| is a diameter of circle PQRS. |PQ| = |QR| and ∠RSP = 74º. Find ∠QPS
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< PQR = 180º - 74º = 106º
<PRQ = \(\frac{180 - 106}{2}\) = 37º ⇒ < QRS = 37º + 90º = 127º
< QPS = 180 - 127 = 53º
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