The angle subtended at the centre by a chord of a circle radius 6cm is 120°. Find the length of the chord.
\(\frac{r}{6} = \sin 60 \)
\(r = 6 \sin 60\)
= \(6 \times \frac{\sqrt{3}}{2}\)
= \(3\sqrt{3}\)
Chord = 2r = \( 2 \times 3\sqrt{3}\)
= \(6\sqrt{3}\)
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