Solve the equation log8x - 4log8x = 2
log\(_8\)x - 4log\(_8\)x = 2; log\(_8\)x - log\(_8\)x\(^4\) = 2 log\(_8\)(\(\frac{\text{x}}{x^4}\)) = 2 \(\frac{\text{x}}{x^4}\) = 8\(^2\) = \(\frac{1}{x^3}\) = 64 x\(^3\) = (\(\frac{1}{4}\))\(^3\);
x = \(\frac{1}{4}\)
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