What is the number whose logarithm to base 10 is \(\bar{3}.4771\)?

Ann_e

1 year ago

We are given:

log_{10}(x) =bar{3}.4771

The bar over the 3 means the characteristic is negative and the mantissa is positive, so:

log{10}(x) = -3 + 0.4771 = -2.5229

Now, to find the number:

x = 10^{-2.5229}

Break it up:

x = 10^{-3 + 0.4771} = 10^{-3}* 10^{0.4771}

But we know:

10^{0.4771} \approx= 3
=> xapprox= 10^{-3}* 3 = 0.001* 3 = 0.003

Final Answer:

D.{0.003}

20annie

1 month ago

that is true