Simplify: 16\(^{\frac{5}{4}}\) x 2\(^{-3}\) x 3\(^0\)
16\(^{\frac{5}{4}}\) x 2\(^{-3}\) x 3\(^0\)
= \((2^4)^{\frac{5}{4}} \times 2^{-3} \times 1\)
= \(2^5 \times 2^{-3} \times 1\)
= \(2^2\)
= 4.
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