Correct Answer: Option A

Explanation

\(\frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)

= \(\frac{(3^3)^{\frac{1}{3}}}{(2^4)^{-\frac{1}{4}}}\)

= \(\frac{3}{2^{-1}}\)

= 6

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