In the diagram above, |PQ| = |QR|, |PS| = |RS|, ∠PSR = 30o and ∠PQR = 80o. Find ∠SPQ.
Join PR QRP = QPR = 180 - 80 = \(\frac{100}{20}\) = 50º SRP = SPR = 180 - 30 = \(\frac{150}{2}\) = 75º ∴ SPQ = SPR - QPR = 75 - 50 = 25º
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