Correct Answer: Option C

Explanation

< STQ = < SQR = 68° (alternate segment)

\(\therefore\) < STQ = 68° 

< TQS = \(\frac{180° - 68°}{2}\)

= \(\frac{112}{2} = 56°\)

\(\therefore\) < PQT = 180° - (68° + 56°)

= 180° - 124°

= 56°

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