Factorize 2x\(^2\) - 21x + 45

a

(2x - 9)(x - 5)

b

(2x-15)(x + 3)

c

(2x +15)(x - 3)

d

(2x -15(x - 3)

e

(2x - 9)(x + 5)

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d

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2x² - 21x + 45
product= 2×45 = 90
sum= -21
factor= -6 -15
2x² - 6x - 15x + 45
2x(x -3) -15(x-3)
(x-3) (2x-15)

bellagal
6 years ago

short method.
open bracket of answer and check if it gives u the original eqtn

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