The nth term of a sequence is given by (-1)\(^{n-2}\) x 2\(^{n-1}\). Find the sum of the second and third terms.
when n = 2
(-1)\(^{n-2}\) 2\(^{n+1}\) = 2
When n = 3
(-1)\(^{n-2}\) 2\(^{n+1}\) = -4
Sum = 2 - 4 = -2
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