What is the probability of throwing a number greater than 2 with a single fair die
1/6
1/3
1/2
2/3
5/6
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A singu die thrown..it wil b 123456 den probability of greater dan 2 is 4 numbas..whic means 4/6=2/3
A fair die has 6 faces, numbered from 1 to 6. To find the probability of throwing a number greater than 2, we need to determine the number of successful outcomes (rolling a number greater than 2) and divide it by the total number of possible outcomes (rolling any number from 1 to 6).
There are 4 successful outcomes: rolling a 3, 4, 5, or 6.
The total number of possible outcomes is 6 (rolling any number from 1 to 6).
So, the probability of throwing a number greater than 2 with a single fair die is:
4 (successful outcomes) / 6 (total possible outcomes) = 2/3 or approximately 0.6667 (when expressed as a decimal).
