In the diagram above, ATR is a tangent at the point T to the circle center O, if ∠TOB = 145°, find ∠TAO
From the figure, < ATO = 90°
< AOT = 180° - 145° = 35°
\(\therefore\) < TAO = 180° - (90° + 35°)
= 55° (sum of angle in a triangle)
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