Simplify: \((\frac{1}{4})^{-1\frac{1}{2}}\)
\((\frac{1}{4})^{-1\frac{1}{2}}\)
= \((\frac{1}{4})^{-\frac{3}{2}}\)
= \((\sqrt{\frac{1}{4}})^{-3}\)
= \((\frac{1}{2})^{-3}\)
= \(2^3\)
= 8
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