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In the diagram above, |PQ| = |PR| = |RS| and ∠RPS = 32°. Find the...

Mathematics
WAEC 1990

In the diagram above, |PQ| = |PR| = |RS| and ∠RPS = 32°. Find the value of ∠QPR

  • A. 72o
  • B. 64o
  • C. 52o
  • D. 32o
  • E. 26o
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Correct Answer: Option C
Explanation

From the figure, < PSR = 32° (base angles of an isos. triangle)

\(\therefore\) < PRS = 180° - (32° + 32°) = 116° (sum of angles in a triangle)

< QRP = 180° - 116° = 64° (angle on a straight line)

< PQR = 64° (base angles of an isos. triangle)

< QPR = 180° - (64° + 64°) = 52°


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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
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