A cylindrical container closed at both ends, has a radius of 7cm and height 5cm [Take π = 22/7]
Find the total surface area of the container
TSA of a cylinder = \(2\pi r^2 + 2\pi rh\)
= \(2\pi r (r + h)\)
= \(2 \times \frac{22}{7} \times 7 (7 + 5)\)
= \(44 \times 12\)
= \(528 cm^2\)
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