An arc of length 22cm subtends an angle of θ at the center of the circle. What is the value of θ if the radius of the circle is 15cm?[Take π = 22/7]
\(2\pi r = 2 \times 3.142 \times 15 = 94.28cm\)
\(94.28cm = 360°\)
\(1cm = \frac{360°}{94.28}\)
\(\therefore 22cm = \frac{360°}{94.28} \times 22\)
= 84°
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