In an A.P the first term is 2, and the sum of the 1st and the 6th term is 161/2. What is the 4th term
1st term a = 2; 6th term = a + (16-1)d = 2 + 5d 2 + (2 + 5d) = 161/2; 4 + 5d = 161/2 5d = 12.5 ∴ = 2.5 the 4th term is 2 + (4-1)2.5= 91/2
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