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sinθ = \(\frac{1}{2}\) and cosθ = -\(\frac{\sqrt{3}}{2}\), what is the value of θ?

Mathematics
WAEC 1989

sinθ = \(\frac{1}{2}\) and cosθ = -\(\frac{\sqrt{3}}{2}\), what is the value of θ?

  • A. 30 0
  • B. 60 0
  • C. 90 o
  • D. 120 o
  • E. 150 o
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Correct Answer: Option E
Explanation

In the 2nd Quadrant, SINE is the only Positive.

Where θ is 30 for the first quadrant and

 150 in the 2nd quadrant, which makes COSINE negative 

Sin θ = \(\frac{1}{2}\)

 θ = Sin\(^{-1}(\frac{1}{2}\)) = 30º which is positive in the first quadrant

Sin 30 = Sin 150, i.e, (180 - 30), which is also positive in the second quadrant.

BUT Cos  θ = -\(\frac{\sqrt{3}}{2}\)

 θ = Cos\(^{-1}\)(-\(\frac{\sqrt{3}}{2}\)) = 150º which is in the second quadrant but negative

Hence,  θ = 150º

 

 

 


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