sinθ = \(\frac{1}{2}\) and cosθ = -\(\frac{\sqrt{3}}{2}\), what is the value of θ?
In the 2nd Quadrant, SINE is the only Positive.
Where θ is 30 for the first quadrant and
150 in the 2nd quadrant, which makes COSINE negative
Sin θ = \(\frac{1}{2}\)
θ = Sin\(^{-1}(\frac{1}{2}\)) = 30º which is positive in the first quadrant
Sin 30 = Sin 150, i.e, (180 - 30), which is also positive in the second quadrant.
BUT Cos θ = -\(\frac{\sqrt{3}}{2}\)
θ = Cos\(^{-1}\)(-\(\frac{\sqrt{3}}{2}\)) = 150º which is in the second quadrant but negative
Hence, θ = 150º
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