In the diagram above, O is the center of the circle QRT and PT is a tangent to the circle at T. Calculate the angle x
< PTQ = <TRQ = 35º
< QTR = 90º
So, < PTR = 35º + 90º = 125º
Therefore, ∠QPT = xº = 180º - 125º - 35º = 20º
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