If twice a certain integer is subtracted from 5 times the integer, the result is 63. Find the integer.
21
9
7
4
3
Explanation
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Discussions (10)
2x²-5x+63=0
(2×63=126)
(2x²-14x) (9x+63)=0
2x(x-7) 9(x-7)=0
(2x+9) (x-7)
2x+9=0 x-7=0
X=-9/2 X=7
X=-4.5 or X=7
so the answer is 7 and not 21
The correct option is A
Working
let the unknown integer be X
first statement => 5*X = 5x
second statement => x *x = 2x.
Third statement => 5x - 2x = 63
3x = 63
x = 21.
Test
5x - 2x = 63, putting the value of x
5(21) - 2(21) = 63
105 - 42 = 63
63 = 63
LHS = RHS...
Thanks.....
The answer is A. 5 multiplied by the integer and then subtracted from the multiplication of 2 x the integer should should give 63. Therefore, the answer is 21.
Let the integer be x
5x-2x=63
3x=63
x=63/3
x=21.
