In the diagram above, PR is perpendicular from P to QS, PQ = 2cm, QR = 1cm and PR = RS. what is the size of the angle QPS?
\(\Delta RPS\) = Isosceles triangle
\(\therefore < RPS = \frac{180° - 90°}{2}\) = 45°
In \(\Delta QPR\),\(\sin < QPR = \frac{1}{2}\) = 30°
\(\therefore < QPS = 30° + 45° = 75°\)
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