Evaluate \(\int 2(2x - 3)^{\frac{2}{3}} \mathrm d x\)
3/5(2x-3)5/3 + k
6/5(2x-3)5/3 + k
2x-3+k
2(2x-3)+k
Explanation
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Discussions (14)
working out wif a phone is quite difficult..well, ah will try. let this symbol (√) be an integral symbol.
we use d method of INTEGRATING BY SUBSTITUTION to crack d little pet .
√2(2x-3)^ 3/4 dx
= √(2x-3)^3/4 2dx
let u = 2x-3
thus, du/dx = 2
cross multiply.
du = 2dx
substitute du for 2dx
√(2x-3)^3/4 2dx
√(2x-3)^3/4 du
Now..it has bcum fitted to be integrated.
the expression ,which is (2x-3), is raised to a power of 3/4. according to d laws integration, we re going to add 1 to d power and,den, divide the expression with d power .
(2x-3)^5/3 ÷ 5/3
= (2x-3)^5/3 × 3/5
= 3/5(2x-3)^5/3
Pls where did the 2 that multiples the values in bracket go to
I think the answer is wrong. It should be B. I need explanation
